The Interactive Geometry Software Cinderella
Forums-> Cinderella Support (E)-> Questions on the speed of custom tools-> Aw: Questions on the speed of custom tools
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Aw: Questions on the speed of custom tools
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> 1. On the speed of custom tools. In the beta version the custom tools work untolerably slow.
> - Creating the new tool takes minutes in the case of a relativeky complicated construction. I have a three year old VAIO note book and a desk top machine of about the same quality...
> - The worst thing is that you have to wait when trying to redefine a point. Why does it take that long for a point to get moving during redefinitions? Also, why does it take that long to hilite the next pont after a having redefined the previous one? Do the custom tools work faster in the final version?
Can you send me an example file (to bugs@cinderella.de) with steps to reproduce? It should not take so long as you describe (though a short delay can happen).
> 2. Sensitivity of invisible objects. Sometimes I have a feeling that invisible (made invisible with the "invisible" check box) objects have some sensitivity. P. ex. I experienced that if a visible point gets close enough to an invisible one then it disappears or jumps on it. Is there something I do wrong? If not am I wrong? Is this OK in the case of the final version?
This should not happen. Again, please send me some steps to reproduce this behavior, and I will check that.
> 3. What happens to a parabola or a pair of hyperbola branches after making them invisible? Why can I not get my such objects back? This can be disastrous in the case of my constructions. I have bee trying to construct the crossing points of 9 parabolas for a week. I have started everything over and over again at least 20 times. Always failed. One of the reasons, in my opinion, is the problem with the phenomena described above .
You can always use the "show all" button to make all elements reappear. Or you can use the construction text (shortcut is control + 4) where all elements, even invisible ones, are visible).
> 4. Crossing point of objects. I would understand if the crossing point of circles and hyperbolas, or hyperbolas and parabolas could not be defined considering that these are not Euclidean constructions. How come that the crossing point of a hyperbola and a parabola can be constructed? This is confusing... Do I do anything wrong? Or just have to be happy that at least in the case of a hy and a par the crossing point works? Or is this corrected in the case of the final?
You can construct the crossing points of circles and hyperbolas, actually you can create all intersection points of two conics. Just use the "add a point" mode and place the point on the intersection.
I am sorry that you experienced such problems - but I am sure we can find out what went wrong. Also, please take my apologies for answering so late, I was away from the Internet during the holiday season most of the time.
Ulli
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